Field guide · Main vents
How many Gorton #2 per main?
The Heating Help / forum question is almost always the same: “how many Gorton #2” or “one #2 per how many feet of main?” The answer is not a fixed rule of thumb — it is main volume divided by the minutes you will give the main to clear, matched to a published vent capacity. This page walks the method; the calculator holds the measured CFM tables.
Direct answer
Gorton #2 = 1.1 / 1.75 / 2.2 CFM at the 1 / 2 / 3 oz chart columns (Gill & Pajek)—not PSI cut-in. Main cu ft ÷ clear minutes ÷ that CFM → #2 count (round up). Forum “one #2 per ~20–25' of 2"” is only a start; size each main in the main vent sizer and cap by the open tapping.
Estimate only
The job in one line
Volume → rate → count.
A one-pipe steam main is full of air when the boiler fires. Main vents at the ends of the mains have to dump that air before steam can fill the pipe. How many Gorton #2 (or #1) eliminators you need depends on three things you can measure or choose:
- Main pipe size and length — nominal ID and run length of each section that vents through the tapping.
- Target minutes — how long you will give the main to clear (often a few minutes; confirm against how the building actually behaves).
- Working boiler pressure — capacities are published at 1 / 2 / 3 oz columns; pick the column that matches how the boiler is set (ounces, not PSI).
Step 1 — Measure the main
Walk each steam main from the boiler header out to the venting point. Note nominal pipe size and length for every section. The calculator converts Schedule 40 internal diameter into cubic feet per linear foot (ASME B36.10M), then multiplies by length.
Add the sections that share the same end-of-main tapping. That sum is the air volume the vents on that tapping must clear.
Step 2 — Volume to required CFM
Required venting rate is straightforward arithmetic used in the Gill & Pajek balancing method:
Example shape only — plug your own lengths into the calculator: a long 2" main holds more air than a short 1-1/4" run, so the same target time demands more vent capacity.
Step 3 — #2 vs #1 count
Divide the required CFM by the published capacity of a Gorton #2 at your working ounce column (1.1 / 1.75 / 2.2 CFM at 1 / 2 / 3 oz). That quotient (rounded up) is how many #2 eliminators to start with. The same math with #1 capacity (0.33 / 0.54 / 0.70 CFM) tells you the alternate count — Gorton states a #2 is equal in venting capacity to four #1 eliminators, and the instrumented Gill & Pajek chart is what the calculator uses for absolute CFM.
Do not copy CFM figures from memory into a takeoff. Open the main vent sizer, enter pipe and time, and read the count from the cited table. Also watch the open-pipe ceiling on the tapping: no stack of vents can pass more air than the tapping itself will allow.
Gorton also catalogs a larger “Big Mouth” main vent; it post-dates the 2005 test program and has no published CFM in that chart, so the calculator shows it as a gap rather than a guessed number. Use it only with manufacturer guidance and field timing — not as a drop-in substitute for a #2 count from the measured table.
Verify on the job
The published method treats the calculated count as a starting point. Pull a vent, fire the boiler, and time steam to the open pipe; reinstall vents until you land near the target. Cold returns, pitched mains, and dirty valves all change the clock.
Next step
Enter the main sizes, lengths, pressure column, and target minutes in the calculator. It applies Schedule 40 volumes and the Gill & Pajek main-vent capacities and returns a #2 / #1 count.
Open main vent sizerRelated: Steam main air volume · Vent ounces and minutes · Gorton C or D on a radiator · All guides
FAQ
How many Gorton #2 main vents do I need?
Schedule 40 main volume ÷ target minutes = required CFM. Divide by published Gorton #2 capacity at your 1/2/3 oz column (1.1 / 1.75 / 2.2 CFM) and round up. Cap by open-pipe tapping capacity. Absolute CFM is in the main vent sizer (Gill & Pajek); Gorton’s “#2 equals four #1” is relative only.
Is one Gorton #2 per 20–25 feet of 2" main enough?
That forum rule of thumb is only a start. A 2" Schedule 40 main holds about 0.023 cu ft per foot; required CFM still depends on your clear minutes and which ounce column you read. Size each main separately in the calculator so a long cold run is not under-vented.
Gorton #2 vs #1 — how many #1 equal one #2?
Gorton states a #2 has venting capacity equal to four #1 eliminators. Absolute CFM from Gill & Pajek: #2 is 1.1 / 1.75 / 2.2 CFM and #1 is 0.33 / 0.54 / 0.70 CFM at 1 / 2 / 3 oz. Use the chart numbers in the sizer, not a mental conversion.
Which ounce column — 1, 2, or 3 oz?
Read the column that matches boiler working pressure in ounces per square inch while the vents are clearing air — not the pressuretrol cut-in in PSI. See /guides/vent-oz-and-minutes.
Sources
Capacities and the balancing procedure come from the public Gill & Pajek PDF. Relative #2 vs #1 claims and placement language come from Gorton's own product materials and air-valve chart. This guide does not invent CFM figures.